Difference between revisions of "Test"

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<math>
 
<math>
x^n + y^n = z^n
 
k_{n+1} = n^2 + k_n^2 - k_{n-1}
 
 
\frac{\mathrm d}{\mathrm d x} \big( I(x) \big)
 
 
 
 
\frac{\mathrm d}{\mathrm d x} \big( I(x) \big)=-\alpha cI(x)
 
\frac{\mathrm d}{\mathrm d x} \big( I(x) \big)=-\alpha cI(x)
 
</math>
 
</math>

Revision as of 22:01, 3 February 2017

[math] \frac{\mathrm d}{\mathrm d x} \big( I(x) \big)=-\alpha cI(x) [/math]