Difference between revisions of "Test"
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| − | \frac{\mathrm d}{\mathrm d x} \big( I(x) \big)=-\alpha | + | \frac{\mathrm d}{\mathrm d x} \big( I(x) \big)=-\alpha cI(x) |
</math> | </math> | ||
Revision as of 22:00, 3 February 2017
[math] x^n + y^n = z^n k_{n+1} = n^2 + k_n^2 - k_{n-1} \frac{\mathrm d}{\mathrm d x} \big( I(x) \big) \frac{\mathrm d}{\mathrm d x} \big( I(x) \big)=-\alpha cI(x) [/math]
