Difference between revisions of "Test"
From Lumipedia
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x^n + y^n = z^n | x^n + y^n = z^n | ||
k_{n+1} = n^2 + k_n^2 - k_{n-1} | k_{n+1} = n^2 + k_n^2 - k_{n-1} | ||
+ | |||
+ | \frac{\mathrm d}{\mathrm d x} \big( I(x) \big) | ||
</math> | </math> |
Revision as of 21:57, 3 February 2017
[math] x^n + y^n = z^n k_{n+1} = n^2 + k_n^2 - k_{n-1} \frac{\mathrm d}{\mathrm d x} \big( I(x) \big) [/math]