Test

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[math] x^n + y^n = z^n k_{n+1} = n^2 + k_n^2 - k_{n-1} \frac{\mathrm d}{\mathrm d x} \big( I(x) \big) \frac{\mathrm d}{\mathrm d x} \big( I(x) \big)=-\alpha, cI(x) [/math]